A115971 - OEIS

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A115971

a(0) = 0. If a(n) = 0, then a(2^n) through a(2^(n+1)-1) are each equal to 1. If a(n) = 1, then a(m + 2^n) = a(m) for each m, 0 <= m <= 2^n -1.

0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 0

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OFFSET

0,1

COMMENTS

Not the characteristic function of A047564, as it does not contain 256, although here a(256) = 1. - Antti Karttunen, Oct 18 2018

LINKS

Antti Karttunen, Table of n, a(n) for n = 0..65537

Index entries for characteristic functions

FORMULA

a(0) = 0; and for n > 0, if a(A000523(n)) is 0, then a(n) = 1, otherwise a(n) = a(n-(2^A000523(n))) = a(A053645(n)). - Antti Karttunen, Oct 22 2018

EXAMPLE

a(2) = 0. So terms a(4) through a(7) are each equal to 1.