MOD: folder reorganized

optim/ex1_10.md → optim/ex1_10/ex1_10.md

@@ -15,7 +15,7 @@ The slot has a width denoted $w_s$ and a height denoted $d_s$. The width of the
 
 The cross-sectional drawing (a) is the view that one would obtain by looking to the right from the left side of the side view (b) if the side view were cut in half (in the direction into the page). The light region indicates a winding comprised of $N$ turns of wire. Our goal in this design will be to design an inductor that has an inductance of at least $L_{mn}$, a flux density below $B_{mx}$, and a current density below $J_{mx}$ at rated dc current $i_{rt}$. It is desirable to minimize the mass $M$ of the inductor and to minimize the power loss at rated current, denoted $P_{rt}$. We will also constrain our designs to have a mass below $M_{mx}$ and a power loss less than $P_{mx}$.
 
-The free parameters in our design are the number of turns $N$, the slot depth $d_s$, the slot width $w_s$, the core thickness $w_c$, the core depth $l_c$, and the air gap $g$. Thus, our parameter vector may be expressed as 
+The free parameters in our design are the number of turns $N$, the slot depth $d_s$, the slot width $w_s$, the core thickness $w_c$, the core depth $l_c$, and the air gap $g$. Thus, our parameter vector may be expressed as:
 $$
 x = [N^*, d_s, w_s,w_c,l_c,g] 
 $$
@@ -62,4 +62,4 @@ In order to formulate a fitness function, expressions (1.10-1)–(1.10-7) can be
 
 For the multi-objective optimization, the fitness function will be taken as
 
-In (1.10-14) and (1.10-15), we will take e = 10−10. For our design, let us consider a ferrite material for the core with Bmx = 0:617 T and rmc = 4680 kg=m3, and consider copper for the wire with rwc = 8890 kg=m3 and Jmx = 7:5 A=mm2. We will take rated current to be 10 A and take the minimum inductance Lmn to be 1 mH. Finally, let us take the maximum allowed mass as Mmx = 1 kg and take the maximum allowed loss to be Pmx = 1 W
+In (1.10-14) and (1.10-15), we will take e = 10−10. For our design, let us consider a ferrite material for the core with Bmx = 0:617 T and rmc = 4680 kg=m3, and consider copper for the wire with rwc = 8890 kg=m3 and Jmx = 7:5 A=mm2. We will take rated current to be 10 A and take the minimum inductance Lmn to be 1 mH. Finally, let us take the maximum allowed mass as Mmx = 1 kg and take the maximum allowed loss to be $Pmx = 1 W