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303. Range Sum Query - Immutable commit.
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liusishan committed Mar 5, 2019
1 parent bf14d48 commit 6e7a442
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8 changes: 8 additions & 0 deletions 09-Segment-Tree/303-Range-Sum-Query-Immutable/src/Merger.java
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/**
* @Auther: lss
* @Date: 2019/2/27 20:53
* @Description:
*/
public interface Merger<E> {
E merge(E a, E b);
}
25 changes: 25 additions & 0 deletions 09-Segment-Tree/303-Range-Sum-Query-Immutable/src/NumArray.java
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/**
* @Auther: lss
* @Date: 2019/3/5 16:58
* @Description:
*/
public class NumArray {

private SegmentTree<Integer> segmentTree;

public NumArray(int[] nums) {
if (nums.length > 0) {
Integer[] data = new Integer[nums.length];
for (int i = 0; i < nums.length; i++)
data[i] = nums[i];
segmentTree = new SegmentTree<>(data, (a, b) -> a + b);
}
}

public int sumRange(int i, int j) {
if (segmentTree == null)
throw new IllegalArgumentException("Segment Tree is null");

return segmentTree.query(i, j);
}
}
110 changes: 110 additions & 0 deletions 09-Segment-Tree/303-Range-Sum-Query-Immutable/src/SegmentTree.java
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/**
* @Auther: lss
* @Date: 2019/2/26 20:53
* @Description:
*/
public class SegmentTree<E> {

private E[] tree;
private E[] data;
private Merger<E> merger;

public SegmentTree(E[] arr, Merger<E> merger) {

this.merger = merger;

data = (E[]) new Object[arr.length];
for (int i = 0; i < arr.length; i++)
data[i] = arr[i];

tree = (E[]) new Object[4 * arr.length];
buildSegmentTree(0, 0, data.length - 1);
}

// 在treeIndex的位置创建表示区间[l...r]的线段树
private void buildSegmentTree(int treeIndex, int l, int r) {

if (l == r) {
tree[treeIndex] = data[l];
return;
}

int leftTreeIndex = leftChild(treeIndex);
int rightTreeIndex = rightChild(treeIndex);
// l+r 可能会溢出 所以采用这种
int mid = l + (r - l) / 2;
buildSegmentTree(leftTreeIndex, l, mid);
buildSegmentTree(rightTreeIndex, mid + 1, r);

tree[treeIndex] = merger.merge(tree[leftTreeIndex], tree[rightTreeIndex]);

}

public int getSize() {
return data.length;
}

public E get(int index) {
if (index < 0 || index >= data.length)
throw new IllegalArgumentException("Index in illegal");
return data[index];
}

// 返回完全二叉树的数组表示中,一个索引所表示的元素的左孩子节点的索引
private int leftChild(int index) {
return 2 * index + 1;
}

// 返回完全二叉树的数组表示中,一个索引所表示的元素的右孩子节点的索引
private int rightChild(int index) {
return 2 * index + 2;
}

// 返回区间[queryL,queryR]的值
public E query(int queryL, int queryR) {

if (queryL < 0 || queryL >= data.length ||
queryR < 0 || queryR >= data.length || queryL > queryR)
throw new IllegalArgumentException("Index is illegal.");

return query(0, 0, data.length - 1, queryL, queryR);
}

// 在以treeId为根的线段树中[l...r]的范围里,搜索区间[queryL...queryR]的值
private E query(int treeIndex, int l, int r, int queryL, int queryR) {

if (l == queryL && r == queryR)
return tree[treeIndex];

int mid = l + (r - l) / 2;
int leftTreeIndex = leftChild(treeIndex);
int rightTreeIndex = rightChild(treeIndex);

if (queryL >= mid + 1)
return query(rightTreeIndex, mid + 1, r, queryL, queryR);
else if (queryR <= mid)
return query(leftTreeIndex, l, mid, queryL, queryR);

E leftResult = query(leftTreeIndex, l, mid, queryL, mid);
E rightResult = query(rightTreeIndex, mid + 1, r, mid + 1, queryR);
return merger.merge(leftResult, rightResult);
}

@Override
public String toString() {
StringBuilder res = new StringBuilder();
res.append('[');
for (int i = 0; i < tree.length; i++) {
if (tree[i] != null)
res.append(tree[i]);
else
res.append("null");

if (i != tree.length - 1)
res.append(", ");
}
res.append(']');
return res.toString();
}

}

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