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Merge pull request #15 from Obvious/master
PeerPicker uses ring hash to more consistently choose peers
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/* | ||
Copyright 2013 Google Inc. | ||
Licensed under the Apache License, Version 2.0 (the "License"); | ||
you may not use this file except in compliance with the License. | ||
You may obtain a copy of the License at | ||
https://www.apache.org/licenses/LICENSE-2.0 | ||
Unless required by applicable law or agreed to in writing, software | ||
distributed under the License is distributed on an "AS IS" BASIS, | ||
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | ||
See the License for the specific language governing permissions and | ||
limitations under the License. | ||
*/ | ||
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// Package consistenthash provides an implementation of a ring hash. | ||
package consistenthash | ||
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import ( | ||
"hash/crc32" | ||
"sort" | ||
"strconv" | ||
) | ||
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type Hash func(data []byte) uint32 | ||
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type Map struct { | ||
hash Hash | ||
replicas int | ||
keys []int // Sorted | ||
hashMap map[int]string | ||
} | ||
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func New(replicas int, fn Hash) *Map { | ||
m := &Map{ | ||
replicas: replicas, | ||
hash: fn, | ||
hashMap: make(map[int]string), | ||
} | ||
if m.hash == nil { | ||
m.hash = crc32.ChecksumIEEE | ||
} | ||
return m | ||
} | ||
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// Returns true if there are no items available. | ||
func (m *Map) IsEmpty() bool { | ||
return len(m.keys) == 0 | ||
} | ||
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// Adds some keys to the hash. | ||
func (m *Map) Add(keys ...string) { | ||
for _, key := range keys { | ||
for i := 0; i < m.replicas; i++ { | ||
hash := int(m.hash([]byte(strconv.Itoa(i) + key))) | ||
m.keys = append(m.keys, hash) | ||
m.hashMap[hash] = key | ||
} | ||
} | ||
sort.Ints(m.keys) | ||
} | ||
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// Gets the closest item in the hash to the provided key. | ||
func (m *Map) Get(key string) string { | ||
if m.IsEmpty() { | ||
return "" | ||
} | ||
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hash := int(m.hash([]byte(key))) | ||
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// Linear search for appropriate replica. | ||
for _, v := range m.keys { | ||
if v >= hash { | ||
return m.hashMap[v] | ||
} | ||
} | ||
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// Means we have cycled back to the first replica. | ||
return m.hashMap[m.keys[0]] | ||
} |
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/* | ||
Copyright 2013 Google Inc. | ||
Licensed under the Apache License, Version 2.0 (the "License"); | ||
you may not use this file except in compliance with the License. | ||
You may obtain a copy of the License at | ||
https://www.apache.org/licenses/LICENSE-2.0 | ||
Unless required by applicable law or agreed to in writing, software | ||
distributed under the License is distributed on an "AS IS" BASIS, | ||
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | ||
See the License for the specific language governing permissions and | ||
limitations under the License. | ||
*/ | ||
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package consistenthash | ||
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import ( | ||
"strconv" | ||
"testing" | ||
) | ||
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func TestHashing(t *testing.T) { | ||
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// Override the hash function to return easier to reason about values. Assumes | ||
// the keys can be converted to an integer. | ||
hash := New(3, func(key []byte) uint32 { | ||
i, err := strconv.Atoi(string(key)) | ||
if err != nil { | ||
panic(err) | ||
} | ||
return uint32(i) | ||
}) | ||
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// Given the above hash function, this will give replicas with "hashes": | ||
// 2, 4, 6, 12, 14, 16, 22, 24, 26 | ||
hash.Add("6", "4", "2") | ||
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testCases := map[string]string{ | ||
"2": "2", | ||
"11": "2", | ||
"23": "4", | ||
"27": "2", | ||
} | ||
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for k, v := range testCases { | ||
if hash.Get(k) != v { | ||
t.Errorf("Asking for %s, should have yielded %s", k, v) | ||
} | ||
} | ||
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// Adds 8, 18, 28 | ||
hash.Add("8") | ||
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// 27 should now map to 8. | ||
testCases["27"] = "8" | ||
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for k, v := range testCases { | ||
if hash.Get(k) != v { | ||
t.Errorf("Asking for %s, should have yielded %s", k, v) | ||
} | ||
} | ||
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} | ||
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func TestConsistency(t *testing.T) { | ||
hash1 := New(1, nil) | ||
hash2 := New(1, nil) | ||
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hash1.Add("Bill", "Bob", "Bonny") | ||
hash2.Add("Bob", "Bonny", "Bill") | ||
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if hash1.Get("Ben") != hash2.Get("Ben") { | ||
t.Errorf("Fetching 'Ben' from both hashes should be the same") | ||
} | ||
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hash2.Add("Becky", "Ben", "Bobby") | ||
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if hash1.Get("Ben") != hash2.Get("Ben") || | ||
hash1.Get("Bob") != hash2.Get("Bob") || | ||
hash1.Get("Bonny") != hash2.Get("Bonny") { | ||
t.Errorf("Direct matches should always return the same entry") | ||
} | ||
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} |
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