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It is a common misunderstanding that
data |> x -> f(x) |> g
parses to
data |> (x -> f(x)) |> g
when it actually parses to
data |> x -> (f(x) |> g)
due to
|>
operator precedence. This can lead to unexpected behavior when using broadcasted pipelining. Using the docstring example with a broadcasted pipeline operator:Having an anonymous function without enclosing parentheses in the docstring for
|>
may promote this misunderstanding.