Improve video quality selection

Wasserflug-tvOS/SupplementalViews/VideoPlayerView.swift

@@ -100,7 +100,7 @@ struct VideoPlayerView: UIViewControllerRepresentable {
  let sparkleTvImage = UIImage(systemName: "sparkles.tv")
  let resolutions: [UIAction] = viewModel.qualityLevels.values
  .sorted(by: { $0.1.order ?? 0 < $1.1.order ?? 0 })
- .reversed()
+ .reversed() // This keeps the higher quality on top of the menu
  .map({ (qualityLevel) -> UIAction in
  return UIAction(title: qualityLevel.1.label, identifier: UIAction.Identifier(qualityLevel.1.name), handler: { _ in
  UserDefaults.standard.set(qualityLevel.1.name, forKey: "DesiredQuality")

Wasserflug-tvOS/ViewModels/VideoViewModel.swift

@@ -139,9 +139,13 @@ class VideoViewModel: BaseViewModel, ObservableObject {
  ])
  var url = qualityLevels[desiredQuality]?.0
  if url == nil {
- url = qualityLevels
- .sorted(by: { Int($0.key) ?? 0 < Int($1.key) ?? 0 })
- .filter({ Int($0.key) ?? 0 < Int(desiredQuality) ?? Int.max }) // Don't get a resolution larger than the desired.
+ let sortedUrls = qualityLevels
+ .sorted(by: { $0.value.1.meta?.video?.height ?? 0 < $1.value.1.meta?.video?.height ?? 0 })
+ // Just get the highest available. It's difficult to be smart about next highest from the selection, because the label isn't
+ // sortable, so let's just guess that if a desired quality isn't available, it's because it was too high and this video
+ // doesn't have it, but the user wants higher quality. It's also an Apple TV instead of a mobiel device, so higher quality
+ // is expected. The expected use case is 4K is desired, but only up to 1080p is available, so default to 1080p.
+ url = sortedUrls
  .last?
  .value.0
  }