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Small Python microservice using FastAPI that receives url links to files and filenames, then returns those files in a zipfile.

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urls_to_zip

A simple Python http microservice created with the FastAPI framework that loads a JSON data structure and responds with a .zip file whose contents are each of the source url named as filename within the final .zip archive.

Sample data below:

[
  {
    "url": "https://media.giphy.com/media/3oz8xD0xvAJ5FCk7Di/giphy.gif",
    "filename": "pic001.gif"
  },
  {
    "url": "https://media.giphy.com/media/l3vRfhFD8hJCiP0uQ/giphy.gif",
    "filename": "pic002.gif"
  },
  ...
]

To Run:

Note: Written in Python 3.9.0

  • Clone the repo and change into the project directory:
git clone [email protected]:HarryLinux/urls_to_zip.git
cd urls_to_zip
  • Create and activate your virtual environment:
python3 -m venv venv
source venv/bin/activate
  • Install the requirements:
pip3 install -r requirements.txt
  • Start the service:
uvicorn main:app

The server should now be running on localhost:8000 (http:https://127.0.0.1:8000)

Endpoints

The service exposes two endpoints, not including the auto-generated docs (Thanks FastAPI)

  • POST /get-zip
    • Request body should contain a list of JSON objects like the one shown above
    • Given the data in the request body is valid, it will return a JSON response with status code 202 as shown below
{
  "message": "Zip file processing, send GET request to /get-zip/<zip_id>",
  "id": <zip_id>
}

FastAPI provides a data validation system that can detect any invalid data type at the runtime
and returns the reason for bad inputs to the user in the JSON format.

  • GET /get-zip/{zip_id}
    • Request should contain the zip_id returned from the POST request
    • If the zipping process has completed, the FileResponse object provided by FastAPI will asynchronously stream the file as the response.
    • Else, you'll receive the appropriate JSON response with either status code 202 or 404 depending on whether zip_id was valid and the process is pending, or the zip_id was invalid, respectively.

Testing

To test the service you could use a client like Insomnia or Postman using the enpoints and protocols mentioned earlier, passing in the appropriate parameters.

or

Using the CLI, you could send curl commands like shown below:

curl -X POST http:https://localhost:8000/get-zip -d '[{"url": "https://media.giphy.com/media/3oz8xD0xvAJ5FCk7Di/giphy.gif", "filename": "pic001.gif"}, {"url": "https://media.giphy.com/media/l3vRfhFD8hJCiP0uQ/giphy.gif", "filename": "pic002.gif"}]'

curl [-X GET] http:https://localhost:8000/get-zip/<zip_id> -o <output_file>.zip

Why FastAPI?

This is a framework I've wanted to try out for a while now after reading about it, but this article does a great job highlighting the benefits and reasoning as to why FastAPI is a great choice over the more common Flask framework, or others for that matter.

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Small Python microservice using FastAPI that receives url links to files and filenames, then returns those files in a zipfile.

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