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Here the pinout of ATMEGA2560 shortly the Mega pinout
Power limit is incorrect - its 200mA per VCC or GND pin - there are 4 of each, so 800mA would be the MAX.
Other chips are the same too - 200mA per VCC/AVCC pin, the total load spread over the ports supports that.
See the "Electrical characteristics" section of the datasheets.
CrossRoads:
Power limit is incorrect - its 200mA per VCC or GND pin - there are 4 of each, so 800mA would be the MAX.
Other chips are the same too - 200mA per VCC/AVCC pin, the total load spread over the ports supports that.
See the "Electrical characteristics" section of the datasheets.
We have discussed this before without reaching agreement as it seems to be based on how one interprets the datasheet. I'm still of the opinion that no AVR 8 bit chip would allow a total device current draw of 800ma and have never seen that total number (800ma) used in any avr datasheet.
Take the 328P for example.
Datasheet in electrical absolute maximum ratings section:
DC Current VCC and GND Pins................................. 200.0mA
Note they say 'Pins' not Pin, so I feel the 200ma value is the maximum total chip current consumption limit.
Comments from any welcomed, I was wrong once before.
It's a beautiful thing! I had recently Googled for the longest time and found some pics of pins, some pics of pin numbers, and still other with different bits of info. This is what I had been searching for. Everything in one place.
I Love your work and the help you give us !!! Thank you
May I would suggest to add the PIN numbers as they are printed on the PCB (you did this on the UNO Reference), this would be easier to use if you don´t screw your Arduino to the printout
Current totals follow the current allowed by the different ports.
Although each I/O port can sink more than the test conditions (20mA at VCC = 5V, 10mA at VCC = 3V) under steady state
conditions (non-transient), the following must be observed:
ATmega640/1280/2560:
1.)The sum of all IOL, for ports J0-J7, A0-A7, G2 should not exceed 200 mA.
2.)The sum of all IOL, for ports C0-C7, G0-G1, D0-D7, L0-L7 should not exceed 200 mA.
3.)The sum of all IOL, for ports G3-G4, B0-B7, H0-B7 should not exceed 200 mA.
4.)The sum of all IOL, for ports E0-E7, G5 should not exceed 100 mA.
5.)The sum of all IOL, for ports F0-F7, K0-K7 should not exceed 100 mA.
If IOL exceeds the test condition, VOL may exceed the related specification. Pins are not guaranteed to sink current greater
than the listed test condition.
That totals 800mA. There is nothing that says if you draw 200mA in one group that you then can't draw it in another.
So this thinking of only 200mA total is nonsense.
That totals 800mA. There is nothing that says if you draw 200mA in one group that you then can't draw it in another.
So this thinking of only 200mA total is nonsense.
LOL, we've had this same discussion before.
There is nothing that says if you draw 200mA in one group that you then can't draw it in another.
There is also nothing stating that you can take the sum, of all those individual port limits, as the maxiumum chip current draw limit. And no where in the datasheet does it state that 800 ma of total current draw is allowed. And of course as I've stated before the absolute maximum section lists the 200 ma figure. Why would they state 200ma there if it only applied to one port? Your assumption, and it is just an assumption, is in error, IMHO.
But that is why I would like others to comment on the subject, as you and I. while still respectful of each other's opinion, have not been able to come to consensus on the matter now or in the past.
