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1869 Ohio gubernatorial election

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1869 Ohio gubernatorial election

← 1867 October 12, 1869 1871 →
 
Nominee Rutherford B. Hayes George H. Pendleton
Party Republican Democratic
Popular vote 236,082 228,581
Percentage 50.74% 49.13%

County results
Hayes:      50–60%      60–70%      70–80%      80–90%
Pendleton:      50–60%      60–70%      70–80%

Governor before election

Rutherford B. Hayes
Republican

Elected Governor

Rutherford B. Hayes
Republican

The 1869 Ohio gubernatorial election was held on October 12, 1869. Incumbent Republican Rutherford B. Hayes defeated Democratic nominee George H. Pendleton with 50.74% of the vote.

General election

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Candidates

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  • Rutherford B. Hayes, incumbent Governor (Republican)
  • George H. Pendleton, former U.S. Representative from Cincinnati, nominee for Vice President of the United States in 1864, and candidate for President in 1868 (Democratic)
  • Samuel Scott (Prohibition)

Results

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1869 Ohio gubernatorial election[1]
Party Candidate Votes % ±%
Republican Rutherford B. Hayes (incumbent) 236,082 50.74%
Democratic George H. Pendleton 228,581 49.13%
Prohibition Samuel Scott 629 0.14%
Majority 7,501
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. elections. ISBN 9781483380353. Retrieved 2020-07-26.