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Question: Matching SMEFT and WET at one loop #68
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Hint: you can enclose inline code in ` and display code blocks in ```python ... ``` to make it more readable. |
I agree with your conversion factor but disagree with there being a discrepancy. Can you check your numerics? |
Thanks a lot for the fast reply! |
I'm too lazy to look up the right values, but using rough values I get: v=246.22
Vtb=1
Vts=-0.04
mb=3
g3 = 1.2
print(wc2['dG_23'] / (1/v**2*Vtb*Vts/(8*pi**2)*mb*g3)) The result is |
Ok, then it might just be some issue with my numerics. Just wanted to check that I did not mess up anything. |
Dear all,
we currently want to use wilson to test our results from our implementation of the matching between SMEFT and WET (especially the flavio basis). However, I ran into some issues and would like to ask whether it is just me not understanding how to use wilson correctly.
So, the example is the following: Say that we want to match 'CuG_33' to 'C8_bs' and as a cross check to 'CdG_23' (in the basis JMS)
The commands I use are:
now, taking conversion factors (vT2 * 8 * pi2 /(g3 * mb) * 1 / ( Vtb * Vts)) between flavio and JMS basis into account, the results differ by a factor of 10:
C8_bs = -0.028...
CdG_23 = 8.725e-10 (= 0.0029... after conversion)
Furthermore, they are in conflict with results obtained when I directly use the corresponding code in 'smeft_loop.py', which agrees with our implementation of the matching in https://arxiv.org/pdf/1512.02830.pdf (after taking the conversion factor into account). This result reads -0.041
Maybe I am just mixing different conventions by mistake or do not use wilson correctly?
Thank you in advance for your help.
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