app.py gives Exec format error

[s4surya1swaiting]

• Serving Flask app "app" (lazy loading)
• Environment: production
  WARNING: This is a development server. Do not use it in a production deployment.
  Use a production WSGI server instead.
• Debug mode: on
  INFO:werkzeug: * Running on http:https://0.0.0.0:5001/ (Press CTRL+C to quit)
  INFO:werkzeug: * Restarting with stat
  Traceback (most recent call last):
  File "app.py", line 278, in
  app.run(host='0.0.0.0', port=PORT)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/flask/app.py", line 990, in run
  run_simple(host, port, self, **options)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/werkzeug/serving.py", line 1007, in run_simple
  run_with_reloader(inner, extra_files, reloader_interval, reloader_type)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/werkzeug/_reloader.py", line 332, in run_with_reloader
  sys.exit(reloader.restart_with_reloader())
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/werkzeug/_reloader.py", line 176, in restart_with_reloader
  exit_code = subprocess.call(args, env=new_environ, close_fds=False)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 172, in call
  return Popen(*popenargs, **kwargs).wait()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 394, in init
  errread, errwrite)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 1047, in _execute_child
  raise child_exception
  OSError: [Errno 8] Exec format error