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Integrals with lb > ub #141
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I'm pretty sure that's not supported for a reason, while I couldn't found cases where the lower bound is higher then the higher bound. I guess that's just isn't needed (meaning for infinite positive lower bound). |
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Similar to how
Inf
bounds are handled, we should handle this case by an automatic transformation.Particularly because the
Inf
bound handling implicitly assumes thatlb < ub
, and integrals from+inf
toa
might give incorrect results.The text was updated successfully, but these errors were encountered: