Arithmetic operators convert Int32 to Int64

[danluu]

julia> i32 = int32(1)
1

julia> x = i32 + i32
2

julia> typeof(x)
Int64

I'd expect x to be Int32 here, and the fact that it's not means that I need to wrap all sorts of stuff in int32; that's probably not even sufficient if I don't break down every expression so that it only has one operator, otherwise I'll still have internal Int64s floating around in something like int32((a + b) * c).

@astrieanna mentioned that there's probably already a bug on this, but neither of us could find it.

[ivarne]

There has been lots of discussion on this, and lots of us think the behaviour is wrong (and that it should be changed). It is at least mentioned in the FAQ, but not as prominent as it should.

[IainNZ]

i believe this is changing in 0.4 release, but I could be wrong.

[JeffBezanson]

At least these: #1078 #3759 #5413 #5806 #7338 #6211
Then I got tired of searching.

[StefanKarpinski]

Yes, we're going to change this in the next major release.