Issue with eachmatch

[bdeonovic]

I wrote this simple regex to grab words (with possible fancy characters)

for m in eachmatch(r"(\p{L}+)", "testing you")
       @show m
end
m = RegexMatch("testing", 1="testing")
m = RegexMatch("you", 1="you")

seems to work:

prompt="¿Cuál es tu pregunta?"
"¿Cuál es tu pregunta?"

Main> for m in eachmatch(r"(\p{L}+)", prompt)
              @show m
       end
m = RegexMatch("Cuál", 1="Cuál")
m = RegexMatch("es", 1="es")
m = RegexMatch("tu", 1="tu")
m = RegexMatch("pregunta", 1="pregunta")

but it doesn't????

prompt = "Tú lees."
for m in eachmatch(r"(\p{L}+)", prompt)
       @show m
end
ERROR: ArgumentError: invalid SubString index
Stacktrace:
 [1] SubString{String}(::String, ::Int64, ::Int64) at .\strings\types.jl:17
 [2] match(::Regex, ::String, ::Int64, ::UInt32) at .\regex.jl:166
 [3] next(::Base.RegexMatchIterator, ::RegexMatch) at .\regex.jl:343
 [4] anonymous at .\<missing>:?
 [5] eval(::Module, ::Any) at .\boot.jl:235
end

(warning infinite loop): if you try

prompt = "Tú"
for m in eachmatch(r"(\p{L}+)", prompt)
       @show m
end
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
m = RegexMatch("", 1="")
......................

[bdeonovic]

works with match and matchall but not eachmatch

match(r"(\p{L}+)", prompt)
RegexMatch("Tú", 1="Tú")

matchall(r"(\p{L}+)", prompt)
2-element Array{SubString{String},1}:
 "Tú"
 "lees"

[bdeonovic]

On slack @ChrisRackauckas said this was fixed on master so I will go ahead and close.

[ChrisRackauckas]

I think that you mixed up something I said about a change I did to DiffEq master with this. I never referenced this.

[bdeonovic]

Hahaha, I guess I misinterpreted to whom you were responding to!

[stevengj]

The same issue as #26829, with the same fix.