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Line 35: The dual of an [[inflection point]] will give a [[Cusp (singularity)\|cusp]] and two points sharing the same tangent line will give a self-intersection point on the dual. From the projective description, one may compute the dual of the dual:<blockquote><math>(x(x'y''-y'x''),\, y(x'y''-y'x''),\, x'y''-y'x'') = ~~(x'y''-y'x'')~~(x, \, y,\, 1)(x'y''-y'x''),</math></blockquote>which is projectively equivalent to the original curve <math>(x(t),y(t),1)</math>. ==Properties of dual curve==

Dual curve: Difference between revisions